Search a number
-
+
13230124301477 is a prime number
BaseRepresentation
bin1100000010000110000011…
…0110111111110010100101
31201211210021002222021201102
43000201200312333302211
53213230243310121402
644045500223005445
72533562546032256
oct300414066776245
951753232867642
1013230124301477
114240956294516
121598105a39885
1374c798041445
1433a4acc6ab2d
1517e22c5da102
hexc0860dbfca5

13230124301477 has 2 divisors, whose sum is σ = 13230124301478. Its totient is φ = 13230124301476.

The previous prime is 13230124301431. The next prime is 13230124301489. The reversal of 13230124301477 is 77410342103231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10971238545796 + 2258885755681 = 3312286^2 + 1502959^2 .

It is a cyclic number.

It is not a de Polignac number, because 13230124301477 - 212 = 13230124297381 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13230124301477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13230124381477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615062150738 + 6615062150739.

It is an arithmetic number, because the mean of its divisors is an integer number (6615062150739).

Almost surely, 213230124301477 is an apocalyptic number.

It is an amenable number.

13230124301477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13230124301477 is an equidigital number, since it uses as much as digits as its factorization.

13230124301477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84672, while the sum is 38.

The spelling of 13230124301477 in words is "thirteen trillion, two hundred thirty billion, one hundred twenty-four million, three hundred one thousand, four hundred seventy-seven".