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132301322120053 is a prime number
BaseRepresentation
bin11110000101001111001101…
…010011101110101101110101
3122100102212211121120211020101
4132011033031103232231311
5114320111101430320203
61145214215513434101
736603312045031462
oct3605171523565565
9570385747524211
10132301322120053
1139178748280709
1212a08a7110b931
1358a8c658294c8
1424955bd5cc669
1510466dad4441d
hex7853cd4eeb75

132301322120053 has 2 divisors, whose sum is σ = 132301322120054. Its totient is φ = 132301322120052.

The previous prime is 132301322120041. The next prime is 132301322120119. The reversal of 132301322120053 is 350021223103231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69817087458244 + 62484234661809 = 8355662^2 + 7904697^2 .

It is a cyclic number.

It is not a de Polignac number, because 132301322120053 - 25 = 132301322120021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132301322100053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66150661060026 + 66150661060027.

It is an arithmetic number, because the mean of its divisors is an integer number (66150661060027).

Almost surely, 2132301322120053 is an apocalyptic number.

It is an amenable number.

132301322120053 is a deficient number, since it is larger than the sum of its proper divisors (1).

132301322120053 is an equidigital number, since it uses as much as digits as its factorization.

132301322120053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 132301322120053 its reverse (350021223103231), we get a palindrome (482322545223284).

The spelling of 132301322120053 in words is "one hundred thirty-two trillion, three hundred one billion, three hundred twenty-two million, one hundred twenty thousand, fifty-three".