Base | Representation |
---|---|
bin | 11110000101001111111011… |
… | …110111100001010110110010 |
3 | 122100102221212001102120011222 |
4 | 132011033323313201112302 |
5 | 114320114201413120300 |
6 | 1145214425220105042 |
7 | 36603340311412313 |
oct | 3605177367412662 |
9 | 570387761376158 |
10 | 132302103254450 |
11 | 391790091a6528 |
12 | 12a0904a835182 |
13 | 58a905b6053cc |
14 | 249565524660a |
15 | 10467346e1785 |
hex | 7853fbde15b2 |
132302103254450 has 24 divisors (see below), whose sum is σ = 246084180503232. Its totient is φ = 52920353463120.
The previous prime is 132302103254437. The next prime is 132302103254471. The reversal of 132302103254450 is 54452301203231.
It is a super-2 number, since 2×1323021032544502 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132302103254450.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6693134 + ... + 17589833.
It is an arithmetic number, because the mean of its divisors is an integer number (10253507520968).
Almost surely, 2132302103254450 is an apocalyptic number.
132302103254450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132302103254450 is a deficient number, since it is larger than the sum of its proper divisors (113782077248782).
132302103254450 is a wasteful number, since it uses less digits than its factorization.
132302103254450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24391946 (or 24391941 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 132302103254450 its reverse (54452301203231), we get a palindrome (186754404457681).
The spelling of 132302103254450 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred three million, two hundred fifty-four thousand, four hundred fifty".
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