Base | Representation |
---|---|
bin | 1100000010000111001100… |
… | …1101101100111010000011 |
3 | 1201211211001120102100112021 |
4 | 3000201303031230322003 |
5 | 3213231411123241311 |
6 | 44045550543142311 |
7 | 2533603305350032 |
oct | 300416315547203 |
9 | 51754046370467 |
10 | 13230432243331 |
11 | 4240aa40a2816 |
12 | 1598190ba4997 |
13 | 74c816a90064 |
14 | 33a4dbb0a719 |
15 | 17e249667171 |
hex | c087336ce83 |
13230432243331 has 2 divisors, whose sum is σ = 13230432243332. Its totient is φ = 13230432243330.
The previous prime is 13230432243319. The next prime is 13230432243389. The reversal of 13230432243331 is 13334223403231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13230432243331 is a prime.
It is a super-2 number, since 2×132304322433312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13230432243631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615216121665 + 6615216121666.
It is an arithmetic number, because the mean of its divisors is an integer number (6615216121666).
Almost surely, 213230432243331 is an apocalyptic number.
13230432243331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230432243331 is an equidigital number, since it uses as much as digits as its factorization.
13230432243331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 13230432243331 its reverse (13334223403231), we get a palindrome (26564655646562).
The spelling of 13230432243331 in words is "thirteen trillion, two hundred thirty billion, four hundred thirty-two million, two hundred forty-three thousand, three hundred thirty-one".
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