Base | Representation |
---|---|
bin | 11110000101010010000110… |
… | …100011101111011111100111 |
3 | 122100110011212012210200122111 |
4 | 132011102012203233133213 |
5 | 114320133433101240003 |
6 | 1145215452140341451 |
7 | 36603452054324011 |
oct | 3605220643573747 |
9 | 570404765720574 |
10 | 132304430102503 |
11 | 39179aa269494a |
12 | 12a09599b44887 |
13 | 58a933c6ba989 |
14 | 24957d62a31b1 |
15 | 104681db17e6d |
hex | 7854868ef7e7 |
132304430102503 has 2 divisors, whose sum is σ = 132304430102504. Its totient is φ = 132304430102502.
The previous prime is 132304430102479. The next prime is 132304430102519. The reversal of 132304430102503 is 305201034403231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132304430102503 - 237 = 132166991149031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132304437102503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66152215051251 + 66152215051252.
It is an arithmetic number, because the mean of its divisors is an integer number (66152215051252).
Almost surely, 2132304430102503 is an apocalyptic number.
132304430102503 is a deficient number, since it is larger than the sum of its proper divisors (1).
132304430102503 is an equidigital number, since it uses as much as digits as its factorization.
132304430102503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 132304430102503 its reverse (305201034403231), we get a palindrome (437505464505734).
The spelling of 132304430102503 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred thirty million, one hundred two thousand, five hundred three".
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