Base | Representation |
---|---|
bin | 11110000101010111011111… |
… | …001011111110100000001111 |
3 | 122100110201210011111010110102 |
4 | 132011113133023332200033 |
5 | 114320232303233341142 |
6 | 1145222250003001315 |
7 | 36604045252621106 |
oct | 3605273713764017 |
9 | 570421704433412 |
10 | 132310212012047 |
11 | 3918149a3a7093 |
12 | 12a0a73236923b |
13 | 58a9a51537224 |
14 | 2495bc414103d |
15 | 1046a5b521532 |
hex | 7855df2fe80f |
132310212012047 has 2 divisors, whose sum is σ = 132310212012048. Its totient is φ = 132310212012046.
The previous prime is 132310212011993. The next prime is 132310212012089. The reversal of 132310212012047 is 740210212013231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132310212012047 - 212 = 132310212007951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132310212012947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155106006023 + 66155106006024.
It is an arithmetic number, because the mean of its divisors is an integer number (66155106006024).
Almost surely, 2132310212012047 is an apocalyptic number.
132310212012047 is a deficient number, since it is larger than the sum of its proper divisors (1).
132310212012047 is an equidigital number, since it uses as much as digits as its factorization.
132310212012047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 132310212012047 its reverse (740210212013231), we get a palindrome (872520424025278).
The spelling of 132310212012047 in words is "one hundred thirty-two trillion, three hundred ten billion, two hundred twelve million, twelve thousand, forty-seven".
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