Base | Representation |
---|---|
bin | 11110000101010111100101… |
… | …001010001101011010000111 |
3 | 122100110202001011000211002121 |
4 | 132011113211022031122013 |
5 | 114320233004411241403 |
6 | 1145222303542350411 |
7 | 36604050610405414 |
oct | 3605274512153207 |
9 | 570422034024077 |
10 | 132310312212103 |
11 | 39181540a14953 |
12 | 12a0a75ba2b407 |
13 | 58a9a6921aabc |
14 | 2495bd358510b |
15 | 1046a652153bd |
hex | 7855e528d687 |
132310312212103 has 2 divisors, whose sum is σ = 132310312212104. Its totient is φ = 132310312212102.
The previous prime is 132310312212017. The next prime is 132310312212137. The reversal of 132310312212103 is 301212213013231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132310312212103 - 213 = 132310312203911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132310312212503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155156106051 + 66155156106052.
It is an arithmetic number, because the mean of its divisors is an integer number (66155156106052).
Almost surely, 2132310312212103 is an apocalyptic number.
132310312212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
132310312212103 is an equidigital number, since it uses as much as digits as its factorization.
132310312212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 132310312212103 its reverse (301212213013231), we get a palindrome (433522525225334).
The spelling of 132310312212103 in words is "one hundred thirty-two trillion, three hundred ten billion, three hundred twelve million, two hundred twelve thousand, one hundred three".
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