Base | Representation |
---|---|
bin | 1100000010001001110000… |
… | …1101010111011001101111 |
3 | 1201211212211111121002021002 |
4 | 3000202130031113121233 |
5 | 3213234313211133403 |
6 | 44050143112430515 |
7 | 2533626326355035 |
oct | 300423415273157 |
9 | 51755744532232 |
10 | 13231120021103 |
11 | 42413173543a6 |
12 | 15983433a843b |
13 | 74c8c641025a |
14 | 33a5651c2555 |
15 | 17e289c23188 |
hex | c089c35766f |
13231120021103 has 2 divisors, whose sum is σ = 13231120021104. Its totient is φ = 13231120021102.
The previous prime is 13231120021073. The next prime is 13231120021109. The reversal of 13231120021103 is 30112002113231.
It is a happy number.
13231120021103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231120021103 - 230 = 13230046279279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231120021109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615560010551 + 6615560010552.
It is an arithmetic number, because the mean of its divisors is an integer number (6615560010552).
Almost surely, 213231120021103 is an apocalyptic number.
13231120021103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231120021103 is an equidigital number, since it uses as much as digits as its factorization.
13231120021103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13231120021103 its reverse (30112002113231), we get a palindrome (43343122134334).
The spelling of 13231120021103 in words is "thirteen trillion, two hundred thirty-one billion, one hundred twenty million, twenty-one thousand, one hundred three".
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