Base | Representation |
---|---|
bin | 10011010000001111101… |
… | …000001100001100011000 |
3 | 11200111011221212212001210 |
4 | 103100033220030030120 |
5 | 133134213200333422 |
6 | 2451455044343120 |
7 | 164406644315565 |
oct | 23201750141430 |
9 | 4614157785053 |
10 | 1323112121112 |
11 | 470146331931 |
12 | 1945176a4aa0 |
13 | 979cc482252 |
14 | 48078d0186c |
15 | 2463ced110c |
hex | 1340fa0c318 |
1323112121112 has 32 divisors (see below), whose sum is σ = 3337052701680. Its totient is φ = 437134387200.
The previous prime is 1323112121059. The next prime is 1323112121113. The reversal of 1323112121112 is 2111212113231.
It is a super-2 number, since 2×13231121211122 (a number of 25 digits) contains 22 as substring.
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323112121113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 243933889 + ... + 243939312.
Almost surely, 21323112121112 is an apocalyptic number.
1323112121112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1323112121112 is an abundant number, since it is smaller than the sum of its proper divisors (2013940580568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323112121112 is a wasteful number, since it uses less digits than its factorization.
1323112121112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487873323 (or 487873319 counting only the distinct ones).
The product of its digits is 144, while the sum is 21.
Adding to 1323112121112 its reverse (2111212113231), we get a palindrome (3434324234343).
The spelling of 1323112121112 in words is "one trillion, three hundred twenty-three billion, one hundred twelve million, one hundred twenty-one thousand, one hundred twelve".
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