Base | Representation |
---|---|
bin | 1100000010001010001100… |
… | …0010001110001111010101 |
3 | 1201211220010111002021100021 |
4 | 3000202203002032033111 |
5 | 3213240032020244001 |
6 | 44050202323145141 |
7 | 2533632216641605 |
oct | 300424302161725 |
9 | 51756114067307 |
10 | 13231234540501 |
11 | 4241375a6252a |
12 | 15983758151b1 |
13 | 74c914068703 |
14 | 33a5764b2c05 |
15 | 17e294ce4ba1 |
hex | c08a308e3d5 |
13231234540501 has 2 divisors, whose sum is σ = 13231234540502. Its totient is φ = 13231234540500.
The previous prime is 13231234540463. The next prime is 13231234540543. The reversal of 13231234540501 is 10504543213231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7884156399876 + 5347078140625 = 2807874^2 + 2312375^2 .
It is a cyclic number.
It is not a de Polignac number, because 13231234540501 - 27 = 13231234540373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231234540591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615617270250 + 6615617270251.
It is an arithmetic number, because the mean of its divisors is an integer number (6615617270251).
Almost surely, 213231234540501 is an apocalyptic number.
It is an amenable number.
13231234540501 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231234540501 is an equidigital number, since it uses as much as digits as its factorization.
13231234540501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 13231234540501 its reverse (10504543213231), we get a palindrome (23735777753732).
The spelling of 13231234540501 in words is "thirteen trillion, two hundred thirty-one billion, two hundred thirty-four million, five hundred forty thousand, five hundred one".
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