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132313010321113 is a prime number
BaseRepresentation
bin11110000101011010000101…
…111110101011011011011001
3122100111000000011222221211221
4132011122011332223123121
5114320304021120233423
61145223431404252041
736604204512064426
oct3605320576533331
9570430004887757
10132313010321113
11391826a5a2a106
1212a0b193541021
1358aa0a91c18cb
142495daba44d4d
151046b72024e5d
hex785685fab6d9

132313010321113 has 2 divisors, whose sum is σ = 132313010321114. Its totient is φ = 132313010321112.

The previous prime is 132313010321069. The next prime is 132313010321189. The reversal of 132313010321113 is 311123010313231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89045399613769 + 43267610707344 = 9436387^2 + 6577812^2 .

It is an emirp because it is prime and its reverse (311123010313231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132313010321113 is a prime.

It is not a weakly prime, because it can be changed into another prime (132313010321413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156505160556 + 66156505160557.

It is an arithmetic number, because the mean of its divisors is an integer number (66156505160557).

Almost surely, 2132313010321113 is an apocalyptic number.

It is an amenable number.

132313010321113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132313010321113 is an equidigital number, since it uses as much as digits as its factorization.

132313010321113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 132313010321113 its reverse (311123010313231), we get a palindrome (443436020634344).

The spelling of 132313010321113 in words is "one hundred thirty-two trillion, three hundred thirteen billion, ten million, three hundred twenty-one thousand, one hundred thirteen".