Base | Representation |
---|---|
bin | 1100000010001010100000… |
… | …1000101001101111111011 |
3 | 1201211220100110002202112121 |
4 | 3000202220020221233323 |
5 | 3213240220422041443 |
6 | 44050215021222111 |
7 | 2533634306201551 |
oct | 300425010515773 |
9 | 51756313082477 |
10 | 13231320112123 |
11 | 424140a299783 |
12 | 159839a401937 |
13 | 74c9289c9ac9 |
14 | 33a5839c9bd1 |
15 | 17e29c5994ed |
hex | c08a8229bfb |
13231320112123 has 2 divisors, whose sum is σ = 13231320112124. Its totient is φ = 13231320112122.
The previous prime is 13231320112093. The next prime is 13231320112147. The reversal of 13231320112123 is 32121102313231.
It is a strong prime.
It is an emirp because it is prime and its reverse (32121102313231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13231320112123 - 217 = 13231319981051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13231320112163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615660056061 + 6615660056062.
It is an arithmetic number, because the mean of its divisors is an integer number (6615660056062).
Almost surely, 213231320112123 is an apocalyptic number.
13231320112123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231320112123 is an equidigital number, since it uses as much as digits as its factorization.
13231320112123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13231320112123 its reverse (32121102313231), we get a palindrome (45352422425354).
The spelling of 13231320112123 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty million, one hundred twelve thousand, one hundred twenty-three".
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