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13231320112147 is a prime number
BaseRepresentation
bin1100000010001010100000…
…1000101001110000010011
31201211220100110002202120111
43000202220020221300103
53213240220422042042
644050215021222151
72533634306201614
oct300425010516023
951756313082514
1013231320112147
11424140a2997a5
12159839a401957
1374c9289c9b17
1433a5839c9c0b
1517e29c599517
hexc08a8229c13

13231320112147 has 2 divisors, whose sum is σ = 13231320112148. Its totient is φ = 13231320112146.

The previous prime is 13231320112123. The next prime is 13231320112163. The reversal of 13231320112147 is 74121102313231.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13231320112147 - 215 = 13231320079379 is a prime.

It is not a weakly prime, because it can be changed into another prime (13231320110147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615660056073 + 6615660056074.

It is an arithmetic number, because the mean of its divisors is an integer number (6615660056074).

Almost surely, 213231320112147 is an apocalyptic number.

13231320112147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13231320112147 is an equidigital number, since it uses as much as digits as its factorization.

13231320112147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 13231320112147 its reverse (74121102313231), we get a palindrome (87352422425378).

The spelling of 13231320112147 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty million, one hundred twelve thousand, one hundred forty-seven".