Base | Representation |
---|---|
bin | 1100000010001010100000… |
… | …1000101001110000010011 |
3 | 1201211220100110002202120111 |
4 | 3000202220020221300103 |
5 | 3213240220422042042 |
6 | 44050215021222151 |
7 | 2533634306201614 |
oct | 300425010516023 |
9 | 51756313082514 |
10 | 13231320112147 |
11 | 424140a2997a5 |
12 | 159839a401957 |
13 | 74c9289c9b17 |
14 | 33a5839c9c0b |
15 | 17e29c599517 |
hex | c08a8229c13 |
13231320112147 has 2 divisors, whose sum is σ = 13231320112148. Its totient is φ = 13231320112146.
The previous prime is 13231320112123. The next prime is 13231320112163. The reversal of 13231320112147 is 74121102313231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231320112147 - 215 = 13231320079379 is a prime.
It is not a weakly prime, because it can be changed into another prime (13231320110147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615660056073 + 6615660056074.
It is an arithmetic number, because the mean of its divisors is an integer number (6615660056074).
Almost surely, 213231320112147 is an apocalyptic number.
13231320112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231320112147 is an equidigital number, since it uses as much as digits as its factorization.
13231320112147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 13231320112147 its reverse (74121102313231), we get a palindrome (87352422425378).
The spelling of 13231320112147 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty million, one hundred twelve thousand, one hundred forty-seven".
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