Search a number
-
+
13231320112181 is a prime number
BaseRepresentation
bin1100000010001010100000…
…1000101001110000110101
31201211220100110002202121202
43000202220020221300311
53213240220422042211
644050215021222245
72533634306201663
oct300425010516065
951756313082552
1013231320112181
11424140a299826
12159839a401985
1374c9289c9b42
1433a5839c9c33
1517e29c59953b
hexc08a8229c35

13231320112181 has 2 divisors, whose sum is σ = 13231320112182. Its totient is φ = 13231320112180.

The previous prime is 13231320112163. The next prime is 13231320112223. The reversal of 13231320112181 is 18121102313231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12951066340081 + 280253772100 = 3598759^2 + 529390^2 .

It is a cyclic number.

It is not a de Polignac number, because 13231320112181 - 234 = 13214140242997 is a prime.

It is a super-2 number, since 2×132313201121812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13231320142181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615660056090 + 6615660056091.

It is an arithmetic number, because the mean of its divisors is an integer number (6615660056091).

Almost surely, 213231320112181 is an apocalyptic number.

It is an amenable number.

13231320112181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13231320112181 is an equidigital number, since it uses as much as digits as its factorization.

13231320112181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 13231320112181 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty million, one hundred twelve thousand, one hundred eighty-one".