Base | Representation |
---|---|
bin | 1100000010001010100011… |
… | …0010001100011110000111 |
3 | 1201211220101012121000222112 |
4 | 3000202220302030132013 |
5 | 3213240231214032442 |
6 | 44050220050451235 |
7 | 2533634500566311 |
oct | 300425062143607 |
9 | 51756335530875 |
10 | 13231331002247 |
11 | 4241415457686 |
12 | 15983a1b93b1b |
13 | 74c92b040877 |
14 | 33a5852227b1 |
15 | 17e29d4eb082 |
hex | c08a8c8c787 |
13231331002247 has 2 divisors, whose sum is σ = 13231331002248. Its totient is φ = 13231331002246.
The previous prime is 13231331002223. The next prime is 13231331002339. The reversal of 13231331002247 is 74220013313231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13231331002247 - 214 = 13231330985863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231331007247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615665501123 + 6615665501124.
It is an arithmetic number, because the mean of its divisors is an integer number (6615665501124).
Almost surely, 213231331002247 is an apocalyptic number.
13231331002247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231331002247 is an equidigital number, since it uses as much as digits as its factorization.
13231331002247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 13231331002247 its reverse (74220013313231), we get a palindrome (87451344315478).
The spelling of 13231331002247 in words is "thirteen trillion, two hundred thirty-one billion, three hundred thirty-one million, two thousand, two hundred forty-seven".
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