13232131117 has 2 divisors, whose sum is σ = 13232131118. Its totient is φ = 13232131116.

The previous prime is 13232131093. The next prime is 13232131147. The reversal of 13232131117 is 71113123231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11263789161 + 1968341956 = 106131^2 + 44366^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13232131117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13232131091 and 13232131100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13232131147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616065558 + 6616065559.

It is an arithmetic number, because the mean of its divisors is an integer number (6616065559).

Almost surely, 2^13232131117 is an apocalyptic number.

It is an amenable number.

13232131117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13232131117 is an equidigital number, since it uses as much as digits as its factorization.

13232131117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 756, while the sum is 25.

Adding to 13232131117 its reverse (71113123231), we get a palindrome (84345254348).

The spelling of 13232131117 in words is "thirteen billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred seventeen".