Base | Representation |
---|---|
bin | 10011010000010101110… |
… | …100111011010110010111 |
3 | 11200111110012120201020012 |
4 | 103100111310323112113 |
5 | 133134421311421122 |
6 | 2451513241430435 |
7 | 164412346320122 |
oct | 23202564732627 |
9 | 4614405521205 |
10 | 1323216123287 |
11 | 47019a007243 |
12 | 19454649b41b |
13 | 97a17b975b6 |
14 | 48088a553b9 |
15 | 246471c67e2 |
hex | 13415d3b597 |
1323216123287 has 2 divisors, whose sum is σ = 1323216123288. Its totient is φ = 1323216123286.
The previous prime is 1323216123167. The next prime is 1323216123289. The reversal of 1323216123287 is 7823216123231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1323216123287 is a prime.
Together with 1323216123289, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323216123289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661608061643 + 661608061644.
It is an arithmetic number, because the mean of its divisors is an integer number (661608061644).
Almost surely, 21323216123287 is an apocalyptic number.
1323216123287 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323216123287 is an equidigital number, since it uses as much as digits as its factorization.
1323216123287 is an evil number, because the sum of its binary digits is even.
The product of its digits is 145152, while the sum is 41.
The spelling of 1323216123287 in words is "one trillion, three hundred twenty-three billion, two hundred sixteen million, one hundred twenty-three thousand, two hundred eighty-seven".
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