Base | Representation |
---|---|
bin | 1100000010001101110101… |
… | …0110110010111101010111 |
3 | 1201211222122200020210022221 |
4 | 3000203131112302331113 |
5 | 3213244033012343221 |
6 | 44050443355203211 |
7 | 2533665400550236 |
oct | 300433526627527 |
9 | 51758580223287 |
10 | 13232213012311 |
11 | 4241828311917 |
12 | 15985a9446507 |
13 | 74ca3b9a8a07 |
14 | 33a62a418b1d |
15 | 17e300b72541 |
hex | c08dd5b2f57 |
13232213012311 has 2 divisors, whose sum is σ = 13232213012312. Its totient is φ = 13232213012310.
The previous prime is 13232213012273. The next prime is 13232213012357. The reversal of 13232213012311 is 11321031223231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13232213012311 is a prime.
It is a super-2 number, since 2×132322130123112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13232213012411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616106506155 + 6616106506156.
It is an arithmetic number, because the mean of its divisors is an integer number (6616106506156).
Almost surely, 213232213012311 is an apocalyptic number.
13232213012311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232213012311 is an equidigital number, since it uses as much as digits as its factorization.
13232213012311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13232213012311 its reverse (11321031223231), we get a palindrome (24553244235542).
The spelling of 13232213012311 in words is "thirteen trillion, two hundred thirty-two billion, two hundred thirteen million, twelve thousand, three hundred eleven".
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