Base | Representation |
---|---|
bin | 1100000010001101110111… |
… | …0110011101010011001111 |
3 | 1201211222200020212110122111 |
4 | 3000203131312131103033 |
5 | 3213244042123442312 |
6 | 44050444253124451 |
7 | 2533665531236212 |
oct | 300433566352317 |
9 | 51758606773574 |
10 | 13232221312207 |
11 | 4241831a70737 |
12 | 15985b0189727 |
13 | 74ca406237b1 |
14 | 33a62b579779 |
15 | 17e3017618a7 |
hex | c08ddd9d4cf |
13232221312207 has 2 divisors, whose sum is σ = 13232221312208. Its totient is φ = 13232221312206.
The previous prime is 13232221312181. The next prime is 13232221312249. The reversal of 13232221312207 is 70221312223231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13232221312207 - 211 = 13232221310159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13232221912207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616110656103 + 6616110656104.
It is an arithmetic number, because the mean of its divisors is an integer number (6616110656104).
Almost surely, 213232221312207 is an apocalyptic number.
13232221312207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232221312207 is an equidigital number, since it uses as much as digits as its factorization.
13232221312207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 13232221312207 its reverse (70221312223231), we get a palindrome (83453533535438).
The spelling of 13232221312207 in words is "thirteen trillion, two hundred thirty-two billion, two hundred twenty-one million, three hundred twelve thousand, two hundred seven".
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