Base | Representation |
---|---|
bin | 10011010000010110110… |
… | …110100101100000101100 |
3 | 11200111111101222011201122 |
4 | 103100112312211200230 |
5 | 133134440213212330 |
6 | 2451515054400112 |
7 | 164412645525050 |
oct | 23202666454054 |
9 | 4614441864648 |
10 | 1323233335340 |
11 | 4701a87a2984 |
12 | 194550200038 |
13 | 97a1b612a47 |
14 | 4808b055c60 |
15 | 246489765e5 |
hex | 13416da582c |
1323233335340 has 144 divisors (see below), whose sum is σ = 3375059583168. Its totient is φ = 426802937856.
The previous prime is 1323233335301. The next prime is 1323233335373. The reversal of 1323233335340 is 435333323231.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a self number, because there is not a number n which added to its sum of digits gives 1323233335340.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 112351532 + ... + 112363308.
It is an arithmetic number, because the mean of its divisors is an integer number (23437913772).
Almost surely, 21323233335340 is an apocalyptic number.
1323233335340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1323233335340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1687529791584).
1323233335340 is an abundant number, since it is smaller than the sum of its proper divisors (2051826247828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323233335340 is a wasteful number, since it uses less digits than its factorization.
1323233335340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14604 (or 14585 counting only the distinct ones).
The product of its (nonzero) digits is 174960, while the sum is 35.
Adding to 1323233335340 its reverse (435333323231), we get a palindrome (1758566658571).
The spelling of 1323233335340 in words is "one trillion, three hundred twenty-three billion, two hundred thirty-three million, three hundred thirty-five thousand, three hundred forty".
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