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1323247605653 is a prime number
BaseRepresentation
bin10011010000010111101…
…101000001011110010101
311200111112101211011220202
4103100113231001132111
5133140002341340103
62451520324310245
7164413211031341
oct23202755013625
94614471734822
101323247605653
1147020585a426
12194554b42385
1397a2156b20c
144808cccc621
1524649d44988
hex13417b41795

1323247605653 has 2 divisors, whose sum is σ = 1323247605654. Its totient is φ = 1323247605652.

The previous prime is 1323247605611. The next prime is 1323247605679. The reversal of 1323247605653 is 3565067423231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 887407332529 + 435840273124 = 942023^2 + 660182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323247605653 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1323247605598 and 1323247605607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323247605683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661623802826 + 661623802827.

It is an arithmetic number, because the mean of its divisors is an integer number (661623802827).

Almost surely, 21323247605653 is an apocalyptic number.

It is an amenable number.

1323247605653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323247605653 is an equidigital number, since it uses as much as digits as its factorization.

1323247605653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 47.

The spelling of 1323247605653 in words is "one trillion, three hundred twenty-three billion, two hundred forty-seven million, six hundred five thousand, six hundred fifty-three".