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132340041161 is a prime number
BaseRepresentation
bin111101101000000010…
…1001100010111001001
3110122121000010122121222
41323100011030113021
54132013022304121
6140443550211425
712363336534536
oct1732005142711
9418530118558
10132340041161
1151141559749
12217944b3b75
13c630929183
14659619bd8d
1536984e40ab
hex1ed014c5c9

132340041161 has 2 divisors, whose sum is σ = 132340041162. Its totient is φ = 132340041160.

The previous prime is 132340041143. The next prime is 132340041173. The reversal of 132340041161 is 161140043231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108293646400 + 24046394761 = 329080^2 + 155069^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132340041161 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132340041161.

It is not a weakly prime, because it can be changed into another prime (132340041101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170020580 + 66170020581.

It is an arithmetic number, because the mean of its divisors is an integer number (66170020581).

Almost surely, 2132340041161 is an apocalyptic number.

It is an amenable number.

132340041161 is a deficient number, since it is larger than the sum of its proper divisors (1).

132340041161 is an equidigital number, since it uses as much as digits as its factorization.

132340041161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 132340041161 its reverse (161140043231), we get a palindrome (293480084392).

The spelling of 132340041161 in words is "one hundred thirty-two billion, three hundred forty million, forty-one thousand, one hundred sixty-one".