Base | Representation |
---|---|
bin | 111101101000000010… |
… | …1001100010111010101 |
3 | 110122121000010122122102 |
4 | 1323100011030113111 |
5 | 4132013022304143 |
6 | 140443550211445 |
7 | 12363336534554 |
oct | 1732005142725 |
9 | 418530118572 |
10 | 132340041173 |
11 | 5114155975a |
12 | 217944b3b85 |
13 | c630929192 |
14 | 659619bd9b |
15 | 36984e40b8 |
hex | 1ed014c5d5 |
132340041173 has 2 divisors, whose sum is σ = 132340041174. Its totient is φ = 132340041172.
The previous prime is 132340041161. The next prime is 132340041233. The reversal of 132340041173 is 371140043231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130883321284 + 1456719889 = 361778^2 + 38167^2 .
It is a cyclic number.
It is not a de Polignac number, because 132340041173 - 218 = 132339779029 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132340041103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170020586 + 66170020587.
It is an arithmetic number, because the mean of its divisors is an integer number (66170020587).
Almost surely, 2132340041173 is an apocalyptic number.
It is an amenable number.
132340041173 is a deficient number, since it is larger than the sum of its proper divisors (1).
132340041173 is an equidigital number, since it uses as much as digits as its factorization.
132340041173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 132340041173 in words is "one hundred thirty-two billion, three hundred forty million, forty-one thousand, one hundred seventy-three".
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