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13234441543 is a prime number
BaseRepresentation
bin11000101001101010…
…11000110101000111
31021011022221021210121
430110311120311013
5204101004112133
610025124002411
7645650616451
oct142465306507
937138837717
1013234441543
1156815518a4
122694230407
13132bb277cb
148d79552d1
15526d1102d
hex314d58d47

13234441543 has 2 divisors, whose sum is σ = 13234441544. Its totient is φ = 13234441542.

The previous prime is 13234441489. The next prime is 13234441589. The reversal of 13234441543 is 34514443231.

13234441543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13234441543 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13234441499 and 13234441508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13234441643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617220771 + 6617220772.

It is an arithmetic number, because the mean of its divisors is an integer number (6617220772).

Almost surely, 213234441543 is an apocalyptic number.

13234441543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13234441543 is an equidigital number, since it uses as much as digits as its factorization.

13234441543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 34.

Adding to 13234441543 its reverse (34514443231), we get a palindrome (47748884774).

The spelling of 13234441543 in words is "thirteen billion, two hundred thirty-four million, four hundred forty-one thousand, five hundred forty-three".