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1323510047 is a prime number
BaseRepresentation
bin100111011100011…
…0010100100011111
310102020102021110122
41032320302210133
510202304310142
6335155225155
744540435606
oct11670624437
93366367418
101323510047
1161a0a5762
1230b2a81bb
13181279c52
14c7ac0a3d
157b2d61d2
hex4ee3291f

1323510047 has 2 divisors, whose sum is σ = 1323510048. Its totient is φ = 1323510046.

The previous prime is 1323509987. The next prime is 1323510073. The reversal of 1323510047 is 7400153231.

It is an a-pointer prime, because the next prime (1323510073) can be obtained adding 1323510047 to its sum of digits (26).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1323510047 - 222 = 1319315743 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1323509998 and 1323510025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323510847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661755023 + 661755024.

It is an arithmetic number, because the mean of its divisors is an integer number (661755024).

Almost surely, 21323510047 is an apocalyptic number.

1323510047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323510047 is an equidigital number, since it uses as much as digits as its factorization.

1323510047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 1323510047 is about 36380.0776112421. The cubic root of 1323510047 is about 1097.9327695528.

Adding to 1323510047 its reverse (7400153231), we get a palindrome (8723663278).

The spelling of 1323510047 in words is "one billion, three hundred twenty-three million, five hundred ten thousand, forty-seven".