Base | Representation |
---|---|
bin | 111101101001110110… |
… | …1110001111010110111 |
3 | 110122202020212022110021 |
4 | 1323103231301322313 |
5 | 4132124124344112 |
6 | 140454005110011 |
7 | 12365010015346 |
oct | 1732355617267 |
9 | 418666768407 |
10 | 132401012407 |
11 | 51172a13304 |
12 | 217b09b8307 |
13 | c640456231 |
14 | 65a030db5d |
15 | 369da39907 |
hex | 1ed3b71eb7 |
132401012407 has 2 divisors, whose sum is σ = 132401012408. Its totient is φ = 132401012406.
The previous prime is 132401012389. The next prime is 132401012521. The reversal of 132401012407 is 704210104231.
It is a weak prime.
It is an emirp because it is prime and its reverse (704210104231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132401012407 - 27 = 132401012279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132401019407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200506203 + 66200506204.
It is an arithmetic number, because the mean of its divisors is an integer number (66200506204).
Almost surely, 2132401012407 is an apocalyptic number.
132401012407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132401012407 is an equidigital number, since it uses as much as digits as its factorization.
132401012407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 132401012407 its reverse (704210104231), we get a palindrome (836611116638).
The spelling of 132401012407 in words is "one hundred thirty-two billion, four hundred one million, twelve thousand, four hundred seven".
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