13240124112042 has 96 divisors (see below), whose sum is σ = 28816596357120. Its totient is φ = 4393491973920.

The previous prime is 13240124112037. The next prime is 13240124112049. The reversal of 13240124112042 is 24021142104231.

13240124112042 is a `hidden beast` number, since 1 + 3 + 2 + 40 + 1 + 2 + 411 + 204 + 2 = 666.

13240124112042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 13240124111997 and 13240124112015.

It is not an unprimeable number, because it can be changed into a prime (13240124112049) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11384456953 + ... + 11384458115.

It is an arithmetic number, because the mean of its divisors is an integer number (300172878720).

Almost surely, 2^{13240124112042} is an apocalyptic number.

13240124112042 is an abundant number, since it is smaller than the sum of its proper divisors (15576472245078).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13240124112042 is a wasteful number, since it uses less digits than its factorization.

13240124112042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3848 (or 3845 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 13240124112042 its reverse (24021142104231), we get a palindrome (37261266216273).

The spelling of 13240124112042 in words is "thirteen trillion, two hundred forty billion, one hundred twenty-four million, one hundred twelve thousand, forty-two".