Base | Representation |
---|---|
bin | 10011010001000101111… |
… | …001100001001111010111 |
3 | 11200120112102011200011021 |
4 | 103101011321201033113 |
5 | 133143044243232211 |
6 | 2452125252022011 |
7 | 164441341456501 |
oct | 23210571411727 |
9 | 4616472150137 |
10 | 1324022633431 |
11 | 470573294253 |
12 | 194730601907 |
13 | 97b15cb9734 |
14 | 48123bd6d71 |
15 | 24692dd7771 |
hex | 13445e613d7 |
1324022633431 has 2 divisors, whose sum is σ = 1324022633432. Its totient is φ = 1324022633430.
The previous prime is 1324022633407. The next prime is 1324022633473. The reversal of 1324022633431 is 1343362204231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1324022633431 - 213 = 1324022625239 is a prime.
It is a super-4 number, since 4×13240226334314 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324022733431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662011316715 + 662011316716.
It is an arithmetic number, because the mean of its divisors is an integer number (662011316716).
Almost surely, 21324022633431 is an apocalyptic number.
1324022633431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324022633431 is an equidigital number, since it uses as much as digits as its factorization.
1324022633431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 1324022633431 its reverse (1343362204231), we get a palindrome (2667384837662).
The spelling of 1324022633431 in words is "one trillion, three hundred twenty-four billion, twenty-two million, six hundred thirty-three thousand, four hundred thirty-one".
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