Base | Representation |
---|---|
bin | 111101101001111110… |
… | …1001001011001010000 |
3 | 110122202112102222021001 |
4 | 1323103331021121100 |
5 | 4132131142300340 |
6 | 140454231311344 |
7 | 12365056163611 |
oct | 1732375113120 |
9 | 418675388231 |
10 | 132405040720 |
11 | 51175214897 |
12 | 217b221b554 |
13 | c641236954 |
14 | 65a0a7bc08 |
15 | 369e08329a |
hex | 1ed3f49650 |
132405040720 has 40 divisors (see below), whose sum is σ = 307887139944. Its totient is φ = 52954202112.
The previous prime is 132405040673. The next prime is 132405040763. The reversal of 132405040720 is 27040504231.
It can be written as a sum of positive squares in 4 ways, for example, as 11186869824 + 121218170896 = 105768^2 + 348164^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 439552 + ... + 676768.
Almost surely, 2132405040720 is an apocalyptic number.
132405040720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132405040720 is an abundant number, since it is smaller than the sum of its proper divisors (175482099224).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132405040720 is a wasteful number, since it uses less digits than its factorization.
132405040720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244207 (or 244201 counting only the distinct ones).
The product of its (nonzero) digits is 6720, while the sum is 28.
Adding to 132405040720 its reverse (27040504231), we get a palindrome (159445544951).
The spelling of 132405040720 in words is "one hundred thirty-two billion, four hundred five million, forty thousand, seven hundred twenty".
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