Base | Representation |
---|---|
bin | 11000101010011100… |
… | …11011000010000111 |
3 | 1021011210021201000202 |
4 | 30111032123002013 |
5 | 204104144113132 |
6 | 10025520401115 |
7 | 646060451456 |
oct | 142516330207 |
9 | 37153251022 |
10 | 13241004167 |
11 | 5685224456 |
12 | 269647619b |
13 | 13302b4911 |
14 | 8d8782b9d |
15 | 5276aa762 |
hex | 31539b087 |
13241004167 has 2 divisors, whose sum is σ = 13241004168. Its totient is φ = 13241004166.
The previous prime is 13241004131. The next prime is 13241004181. The reversal of 13241004167 is 76140014231.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (76140014231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13241004167 - 218 = 13240742023 is a prime.
It is a super-2 number, since 2×132410041672 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13241000167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620502083 + 6620502084.
It is an arithmetic number, because the mean of its divisors is an integer number (6620502084).
Almost surely, 213241004167 is an apocalyptic number.
13241004167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241004167 is an equidigital number, since it uses as much as digits as its factorization.
13241004167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 13241004167 its reverse (76140014231), we get a palindrome (89381018398).
The spelling of 13241004167 in words is "thirteen billion, two hundred forty-one million, four thousand, one hundred sixty-seven".
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