132411310141127 has 2 divisors, whose sum is σ = 132411310141128. Its totient is φ = 132411310141126.

The previous prime is 132411310141109. The next prime is 132411310141133. The reversal of 132411310141127 is 721141013114231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132411310141127 - 2⁸ = 132411310140871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132411310141093 and 132411310141102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132411310941127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205655070563 + 66205655070564.

It is an arithmetic number, because the mean of its divisors is an integer number (66205655070564).

Almost surely, 2^{132411310141127} is an apocalyptic number.

132411310141127 is a deficient number, since it is larger than the sum of its proper divisors (1).

132411310141127 is an equidigital number, since it uses as much as digits as its factorization.

132411310141127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 32.

Adding to 132411310141127 its reverse (721141013114231), we get a palindrome (853552323255358).

The spelling of 132411310141127 in words is "one hundred thirty-two trillion, four hundred eleven billion, three hundred ten million, one hundred forty-one thousand, one hundred twenty-seven".