1324113200231 has 2 divisors, whose sum is σ = 1324113200232. Its totient is φ = 1324113200230.

The previous prime is 1324113200159. The next prime is 1324113200233. The reversal of 1324113200231 is 1320023114231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1324113200231 is a prime.

It is a super-2 number, since 2×1324113200231² (a number of 25 digits) contains 22 as substring.

Together with 1324113200233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1324113200197 and 1324113200206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324113200233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662056600115 + 662056600116.

It is an arithmetic number, because the mean of its divisors is an integer number (662056600116).

Almost surely, 2^{1324113200231} is an apocalyptic number.

1324113200231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324113200231 is an equidigital number, since it uses as much as digits as its factorization.

1324113200231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1324113200231 its reverse (1320023114231), we get a palindrome (2644136314462).

The spelling of 1324113200231 in words is "one trillion, three hundred twenty-four billion, one hundred thirteen million, two hundred thousand, two hundred thirty-one".