Base | Representation |
---|---|
bin | 1100000010110000100011… |
… | …0000010111101111101110 |
3 | 1201212212201001211020111010 |
4 | 3000230020300113233232 |
5 | 3213422123423241340 |
6 | 44055024141410050 |
7 | 2534445325004412 |
oct | 300541060275756 |
9 | 51785631736433 |
10 | 13241531071470 |
11 | 424577a0a1659 |
12 | 159a369b69926 |
13 | 75089530a9a0 |
14 | 33ac71b84d42 |
15 | 17e698c28b80 |
hex | c0b08c17bee |
13241531071470 has 128 divisors (see below), whose sum is σ = 34264840579200. Its totient is φ = 3255591886848.
The previous prime is 13241531071469. The next prime is 13241531071477. The reversal of 13241531071470 is 7417013514231.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13241531071477) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1589806266 + ... + 1589814594.
It is an arithmetic number, because the mean of its divisors is an integer number (267694067025).
Almost surely, 213241531071470 is an apocalyptic number.
13241531071470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13241531071470 is an abundant number, since it is smaller than the sum of its proper divisors (21023309507730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13241531071470 is a wasteful number, since it uses less digits than its factorization.
13241531071470 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12694.
The product of its (nonzero) digits is 70560, while the sum is 39.
The spelling of 13241531071470 in words is "thirteen trillion, two hundred forty-one billion, five hundred thirty-one million, seventy-one thousand, four hundred seventy".
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