Base | Representation |
---|---|
bin | 11110000111000001011111… |
… | …111000110101001111000111 |
3 | 122100212121121001200120011202 |
4 | 132013001133320311033013 |
5 | 114324113413320411121 |
6 | 1145350433032253115 |
7 | 36615215112160634 |
oct | 3607013770651707 |
9 | 570777531616152 |
10 | 132424040403911 |
11 | 392157a157a713 |
12 | 12a287bb24119b |
13 | 58b76c1c2c559 |
14 | 249b50196718b |
15 | 10499be79240b |
hex | 78705fe353c7 |
132424040403911 has 2 divisors, whose sum is σ = 132424040403912. Its totient is φ = 132424040403910.
The previous prime is 132424040403901. The next prime is 132424040404049. The reversal of 132424040403911 is 119304040424231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132424040403911 - 210 = 132424040402887 is a prime.
It is a super-2 number, since 2×1324240404039112 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132424040403901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66212020201955 + 66212020201956.
It is an arithmetic number, because the mean of its divisors is an integer number (66212020201956).
Almost surely, 2132424040403911 is an apocalyptic number.
132424040403911 is a deficient number, since it is larger than the sum of its proper divisors (1).
132424040403911 is an equidigital number, since it uses as much as digits as its factorization.
132424040403911 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 38.
The spelling of 132424040403911 in words is "one hundred thirty-two trillion, four hundred twenty-four billion, forty million, four hundred three thousand, nine hundred eleven".
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