Base | Representation |
---|---|
bin | 11110000111000001011111… |
… | …111000110101010000101010 |
3 | 122100212121121001200120022102 |
4 | 132013001133320311100222 |
5 | 114324113413320412020 |
6 | 1145350433032253402 |
7 | 36615215112161135 |
oct | 3607013770652052 |
9 | 570777531616272 |
10 | 132424040404010 |
11 | 392157a157a7a3 |
12 | 12a287bb241262 |
13 | 58b76c1c2c604 |
14 | 249b50196721c |
15 | 10499be792475 |
hex | 78705fe3542a |
132424040404010 has 16 divisors (see below), whose sum is σ = 252384641711496. Its totient is φ = 49853756387328.
The previous prime is 132424040403911. The next prime is 132424040404049. The reversal of 132424040404010 is 10404040424231.
It can be written as a sum of positive squares in 4 ways, for example, as 123658870280401 + 8765170123609 = 11120201^2 + 2960603^2 .
It is a super-3 number, since 3×1324240404040103 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 389482471607 + ... + 389482471946.
Almost surely, 2132424040404010 is an apocalyptic number.
132424040404010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132424040404010 is a deficient number, since it is larger than the sum of its proper divisors (119960601307486).
132424040404010 is a wasteful number, since it uses less digits than its factorization.
132424040404010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 778964943577.
The product of its (nonzero) digits is 12288, while the sum is 29.
Adding to 132424040404010 its reverse (10404040424231), we get a palindrome (142828080828241).
The spelling of 132424040404010 in words is "one hundred thirty-two trillion, four hundred twenty-four billion, forty million, four hundred four thousand, ten".
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