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1324254998837 is a prime number
BaseRepresentation
bin10011010001010011101…
…111111011000100110101
311200121010121102001120102
4103101103233323010311
5133144033234430322
62452204312243445
7164450162523611
oct23212357730465
94617117361512
101324254998837
11470682472881
121947963a0585
1397b52196564
1448146a02341
15246a84d6792
hex13453bfb135

1324254998837 has 2 divisors, whose sum is σ = 1324254998838. Its totient is φ = 1324254998836.

The previous prime is 1324254998813. The next prime is 1324254998839. The reversal of 1324254998837 is 7388994524231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1298811239716 + 25443759121 = 1139654^2 + 159511^2 .

It is a cyclic number.

It is not a de Polignac number, because 1324254998837 - 232 = 1319960031541 is a prime.

Together with 1324254998839, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324254998839) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662127499418 + 662127499419.

It is an arithmetic number, because the mean of its divisors is an integer number (662127499419).

Almost surely, 21324254998837 is an apocalyptic number.

It is an amenable number.

1324254998837 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324254998837 is an equidigital number, since it uses as much as digits as its factorization.

1324254998837 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 104509440, while the sum is 65.

The spelling of 1324254998837 in words is "one trillion, three hundred twenty-four billion, two hundred fifty-four million, nine hundred ninety-eight thousand, eight hundred thirty-seven".