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132435112541 is a prime number
BaseRepresentation
bin111101101010110111…
…1110111001001011101
3110122211122000210001012
41323111233313021131
54132211342100131
6140501224025005
712365602611554
oct1732557671135
9418748023035
10132435112541
1151190194236
1221800302165
13c647535524
1465a4a68d9b
1536a1a2352b
hex1ed5bf725d

132435112541 has 2 divisors, whose sum is σ = 132435112542. Its totient is φ = 132435112540.

The previous prime is 132435112531. The next prime is 132435112547. The reversal of 132435112541 is 145211534231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130498672516 + 1936440025 = 361246^2 + 44005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132435112541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132435112498 and 132435112507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132435112547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66217556270 + 66217556271.

It is an arithmetic number, because the mean of its divisors is an integer number (66217556271).

Almost surely, 2132435112541 is an apocalyptic number.

It is an amenable number.

132435112541 is a deficient number, since it is larger than the sum of its proper divisors (1).

132435112541 is an equidigital number, since it uses as much as digits as its factorization.

132435112541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 32.

Adding to 132435112541 its reverse (145211534231), we get a palindrome (277646646772).

The spelling of 132435112541 in words is "one hundred thirty-two billion, four hundred thirty-five million, one hundred twelve thousand, five hundred forty-one".