Base | Representation |
---|---|
bin | 111101101010110111… |
… | …1110111001001011101 |
3 | 110122211122000210001012 |
4 | 1323111233313021131 |
5 | 4132211342100131 |
6 | 140501224025005 |
7 | 12365602611554 |
oct | 1732557671135 |
9 | 418748023035 |
10 | 132435112541 |
11 | 51190194236 |
12 | 21800302165 |
13 | c647535524 |
14 | 65a4a68d9b |
15 | 36a1a2352b |
hex | 1ed5bf725d |
132435112541 has 2 divisors, whose sum is σ = 132435112542. Its totient is φ = 132435112540.
The previous prime is 132435112531. The next prime is 132435112547. The reversal of 132435112541 is 145211534231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130498672516 + 1936440025 = 361246^2 + 44005^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132435112541 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132435112498 and 132435112507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132435112547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66217556270 + 66217556271.
It is an arithmetic number, because the mean of its divisors is an integer number (66217556271).
Almost surely, 2132435112541 is an apocalyptic number.
It is an amenable number.
132435112541 is a deficient number, since it is larger than the sum of its proper divisors (1).
132435112541 is an equidigital number, since it uses as much as digits as its factorization.
132435112541 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 32.
Adding to 132435112541 its reverse (145211534231), we get a palindrome (277646646772).
The spelling of 132435112541 in words is "one hundred thirty-two billion, four hundred thirty-five million, one hundred twelve thousand, five hundred forty-one".
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