Base | Representation |
---|---|
bin | 10011010001011001101… |
… | …111011010111000000001 |
3 | 11200121101121120120201202 |
4 | 103101121233122320001 |
5 | 133144240003431431 |
6 | 2452222303110545 |
7 | 164452523161232 |
oct | 23213157327001 |
9 | 4617347516652 |
10 | 1324355530241 |
11 | 470724197587 |
12 | 194803ba2455 |
13 | 97b69c64bb3 |
14 | 481560d1089 |
15 | 246b22438cb |
hex | 13459bdae01 |
1324355530241 has 2 divisors, whose sum is σ = 1324355530242. Its totient is φ = 1324355530240.
The previous prime is 1324355530189. The next prime is 1324355530243. The reversal of 1324355530241 is 1420355534231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1078681651216 + 245673879025 = 1038596^2 + 495655^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1324355530241 is a prime.
Together with 1324355530243, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1324355530195 and 1324355530204.
It is not a weakly prime, because it can be changed into another prime (1324355530243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662177765120 + 662177765121.
It is an arithmetic number, because the mean of its divisors is an integer number (662177765121).
Almost surely, 21324355530241 is an apocalyptic number.
It is an amenable number.
1324355530241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324355530241 is an equidigital number, since it uses as much as digits as its factorization.
1324355530241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 38.
The spelling of 1324355530241 in words is "one trillion, three hundred twenty-four billion, three hundred fifty-five million, five hundred thirty thousand, two hundred forty-one".
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