Base | Representation |
---|---|
bin | 10011010001011100101… |
… | …000111000111100011000 |
3 | 11200121112000001201120001 |
4 | 103101130220320330120 |
5 | 133144334430300130 |
6 | 2452231201142344 |
7 | 164453653350016 |
oct | 23213450707430 |
9 | 4617460051501 |
10 | 1324404150040 |
11 | 470749685334 |
12 | 19481832a9b4 |
13 | 97b77058cca |
14 | 4815c7498b6 |
15 | 246b66496ca |
hex | 1345ca38f18 |
1324404150040 has 32 divisors (see below), whose sum is σ = 3024385602480. Its totient is φ = 521854768512.
The previous prime is 1324404150031. The next prime is 1324404150073. The reversal of 1324404150040 is 400514044231.
It is a junction number, because it is equal to n+sod(n) for n = 1324404149990 and 1324404150008.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 247087647 + ... + 247093006.
Almost surely, 21324404150040 is an apocalyptic number.
1324404150040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1324404150040 is an abundant number, since it is smaller than the sum of its proper divisors (1699981452440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1324404150040 is a wasteful number, since it uses less digits than its factorization.
1324404150040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 494180731 (or 494180727 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 1324404150040 its reverse (400514044231), we get a palindrome (1724918194271).
The spelling of 1324404150040 in words is "one trillion, three hundred twenty-four billion, four hundred four million, one hundred fifty thousand, forty".
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