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13244204449999 is a prime number
BaseRepresentation
bin1100000010111010100000…
…0110100000000011001111
31201220010121101020221101201
43000232220012200003033
53213443112314344444
644100145321250331
72534601506233045
oct300565006400317
951803541227351
1013244204449999
1142469211554a6
12159a9953339a7
13750c00133183
1433b046c48395
1517e7a37a0dd4
hexc0ba81a00cf

13244204449999 has 2 divisors, whose sum is σ = 13244204450000. Its totient is φ = 13244204449998.

The previous prime is 13244204449981. The next prime is 13244204450039. The reversal of 13244204449999 is 99994440244231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13244204449999 - 25 = 13244204449967 is a prime.

It is a super-2 number, since 2×132442044499992 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13244204449999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13244204449199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622102224999 + 6622102225000.

It is an arithmetic number, because the mean of its divisors is an integer number (6622102225000).

Almost surely, 213244204449999 is an apocalyptic number.

13244204449999 is a deficient number, since it is larger than the sum of its proper divisors (1).

13244204449999 is an equidigital number, since it uses as much as digits as its factorization.

13244204449999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80621568, while the sum is 64.

The spelling of 13244204449999 in words is "thirteen trillion, two hundred forty-four billion, two hundred four million, four hundred forty-nine thousand, nine hundred ninety-nine".