Base | Representation |
---|---|
bin | 111101101011010100… |
… | …0110111010101010111 |
3 | 110122212200010221221112 |
4 | 1323112220313111113 |
5 | 4132224203234021 |
6 | 140502520205235 |
7 | 12366143616224 |
oct | 1732650672527 |
9 | 418780127845 |
10 | 132450055511 |
11 | 511986700a4 |
12 | 2180530981b |
13 | c64a667c17 |
14 | 65a6a3894b |
15 | 36a2ec5d5b |
hex | 1ed6a37557 |
132450055511 has 2 divisors, whose sum is σ = 132450055512. Its totient is φ = 132450055510.
The previous prime is 132450055457. The next prime is 132450055561. The reversal of 132450055511 is 115550054231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132450055511 is a prime.
It is a super-2 number, since 2×1324500555112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132450055561) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66225027755 + 66225027756.
It is an arithmetic number, because the mean of its divisors is an integer number (66225027756).
Almost surely, 2132450055511 is an apocalyptic number.
132450055511 is a deficient number, since it is larger than the sum of its proper divisors (1).
132450055511 is an equidigital number, since it uses as much as digits as its factorization.
132450055511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15000, while the sum is 32.
The spelling of 132450055511 in words is "one hundred thirty-two billion, four hundred fifty million, fifty-five thousand, five hundred eleven".
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