Base | Representation |
---|---|
bin | 11000101011000110… |
… | …11010000101111101 |
3 | 1021012011122012012221 |
4 | 30111203122011331 |
5 | 204112101132331 |
6 | 10030234325341 |
7 | 646155303046 |
oct | 142543320575 |
9 | 37164565187 |
10 | 13246505341 |
11 | 5688341583 |
12 | 2698289851 |
13 | 133148c854 |
14 | 8d93b58cd |
15 | 527de5711 |
hex | 3158da17d |
13246505341 has 2 divisors, whose sum is σ = 13246505342. Its totient is φ = 13246505340.
The previous prime is 13246505273. The next prime is 13246505347. The reversal of 13246505341 is 14350564231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12046160025 + 1200345316 = 109755^2 + 34646^2 .
It is an emirp because it is prime and its reverse (14350564231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13246505341 - 213 = 13246497149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13246505297 and 13246505306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13246505347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623252670 + 6623252671.
It is an arithmetic number, because the mean of its divisors is an integer number (6623252671).
Almost surely, 213246505341 is an apocalyptic number.
It is an amenable number.
13246505341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13246505341 is an equidigital number, since it uses as much as digits as its factorization.
13246505341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 13246505341 in words is "thirteen billion, two hundred forty-six million, five hundred five thousand, three hundred forty-one".
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