Search a number
-
+
13247870889677 is a prime number
BaseRepresentation
bin1100000011001000001010…
…1000110110111011001101
31201220111001220022101002212
43000302002220312323031
53214023114421432202
644101553214000205
72535061406402414
oct300620250667315
951814056271085
1013247870889677
114248432822936
12159b6391a6065
137513659063c8
1433b2b3b7047b
1517e91a5d8652
hexc0c82a36ecd

13247870889677 has 2 divisors, whose sum is σ = 13247870889678. Its totient is φ = 13247870889676.

The previous prime is 13247870889599. The next prime is 13247870889679. The reversal of 13247870889677 is 77698807874231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13069338443716 + 178532445961 = 3615154^2 + 422531^2 .

It is a cyclic number.

It is not a de Polignac number, because 13247870889677 - 224 = 13247854112461 is a prime.

Together with 13247870889679, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13247870889598 and 13247870889607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13247870889679) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623935444838 + 6623935444839.

It is an arithmetic number, because the mean of its divisors is an integer number (6623935444839).

Almost surely, 213247870889677 is an apocalyptic number.

It is an amenable number.

13247870889677 is a deficient number, since it is larger than the sum of its proper divisors (1).

13247870889677 is an equidigital number, since it uses as much as digits as its factorization.

13247870889677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1593188352, while the sum is 77.

The spelling of 13247870889677 in words is "thirteen trillion, two hundred forty-seven billion, eight hundred seventy million, eight hundred eighty-nine thousand, six hundred seventy-seven".