Base | Representation |
---|---|
bin | 11110001000001111011000… |
… | …101011000110011010100111 |
3 | 122101011121110102211111202202 |
4 | 132020033120223012122213 |
5 | 114332001202313213043 |
6 | 1145453103411125115 |
7 | 36624235422345512 |
oct | 3610173053063247 |
9 | 571147412744682 |
10 | 132507671226023 |
11 | 39248207a37125 |
12 | 12a40a5aba379b |
13 | 58c255c346702 |
14 | 24a15969d5d79 |
15 | 104bc668b01b8 |
hex | 7883d8ac66a7 |
132507671226023 has 2 divisors, whose sum is σ = 132507671226024. Its totient is φ = 132507671226022.
The previous prime is 132507671225947. The next prime is 132507671226113. The reversal of 132507671226023 is 320622176705231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132507671226023 - 220 = 132507670177447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132507631226023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66253835613011 + 66253835613012.
It is an arithmetic number, because the mean of its divisors is an integer number (66253835613012).
Almost surely, 2132507671226023 is an apocalyptic number.
132507671226023 is a deficient number, since it is larger than the sum of its proper divisors (1).
132507671226023 is an equidigital number, since it uses as much as digits as its factorization.
132507671226023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1270080, while the sum is 47.
The spelling of 132507671226023 in words is "one hundred thirty-two trillion, five hundred seven billion, six hundred seventy-one million, two hundred twenty-six thousand, twenty-three".
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