Base | Representation |
---|---|
bin | 11110001000010001110000… |
… | …001100000000010010101011 |
3 | 122101011212000121000202000212 |
4 | 132020101300030000102223 |
5 | 114332021404040230212 |
6 | 1145454203534451335 |
7 | 36624355420021361 |
oct | 3610216014002253 |
9 | 571155017022025 |
10 | 132510213211307 |
11 | 392492a1907308 |
12 | 12a4144a363b4b |
13 | 58c2875b86209 |
14 | 24a1758455631 |
15 | 104bd64b30e22 |
hex | 7884703004ab |
132510213211307 has 2 divisors, whose sum is σ = 132510213211308. Its totient is φ = 132510213211306.
The previous prime is 132510213211261. The next prime is 132510213211331. The reversal of 132510213211307 is 703112312015231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132510213211307 - 226 = 132510146102443 is a prime.
It is not a weakly prime, because it can be changed into another prime (132510213211807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66255106605653 + 66255106605654.
It is an arithmetic number, because the mean of its divisors is an integer number (66255106605654).
Almost surely, 2132510213211307 is an apocalyptic number.
132510213211307 is a deficient number, since it is larger than the sum of its proper divisors (1).
132510213211307 is an equidigital number, since it uses as much as digits as its factorization.
132510213211307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 132510213211307 its reverse (703112312015231), we get a palindrome (835622525226538).
The spelling of 132510213211307 in words is "one hundred thirty-two trillion, five hundred ten billion, two hundred thirteen million, two hundred eleven thousand, three hundred seven".
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