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132510213211307 is a prime number
BaseRepresentation
bin11110001000010001110000…
…001100000000010010101011
3122101011212000121000202000212
4132020101300030000102223
5114332021404040230212
61145454203534451335
736624355420021361
oct3610216014002253
9571155017022025
10132510213211307
11392492a1907308
1212a4144a363b4b
1358c2875b86209
1424a1758455631
15104bd64b30e22
hex7884703004ab

132510213211307 has 2 divisors, whose sum is σ = 132510213211308. Its totient is φ = 132510213211306.

The previous prime is 132510213211261. The next prime is 132510213211331. The reversal of 132510213211307 is 703112312015231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132510213211307 - 226 = 132510146102443 is a prime.

It is not a weakly prime, because it can be changed into another prime (132510213211807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66255106605653 + 66255106605654.

It is an arithmetic number, because the mean of its divisors is an integer number (66255106605654).

Almost surely, 2132510213211307 is an apocalyptic number.

132510213211307 is a deficient number, since it is larger than the sum of its proper divisors (1).

132510213211307 is an equidigital number, since it uses as much as digits as its factorization.

132510213211307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 132510213211307 its reverse (703112312015231), we get a palindrome (835622525226538).

The spelling of 132510213211307 in words is "one hundred thirty-two trillion, five hundred ten billion, two hundred thirteen million, two hundred eleven thousand, three hundred seven".