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132510213211331 is a prime number
BaseRepresentation
bin11110001000010001110000…
…001100000000010011000011
3122101011212000121000202001202
4132020101300030000103003
5114332021404040230311
61145454203534451415
736624355420021424
oct3610216014002303
9571155017022052
10132510213211331
11392492a190732a
1212a4144a363b6b
1358c2875b86227
1424a175845564b
15104bd64b30e3b
hex7884703004c3

132510213211331 has 2 divisors, whose sum is σ = 132510213211332. Its totient is φ = 132510213211330.

The previous prime is 132510213211307. The next prime is 132510213211339. The reversal of 132510213211331 is 133112312015231.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (133112312015231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132510213211331 is a prime.

It is a super-2 number, since 2×1325102132113312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132510213211294 and 132510213211303.

It is not a weakly prime, because it can be changed into another prime (132510213211339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66255106605665 + 66255106605666.

It is an arithmetic number, because the mean of its divisors is an integer number (66255106605666).

Almost surely, 2132510213211331 is an apocalyptic number.

132510213211331 is a deficient number, since it is larger than the sum of its proper divisors (1).

132510213211331 is an equidigital number, since it uses as much as digits as its factorization.

132510213211331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 29.

Adding to 132510213211331 its reverse (133112312015231), we get a palindrome (265622525226562).

The spelling of 132510213211331 in words is "one hundred thirty-two trillion, five hundred ten billion, two hundred thirteen million, two hundred eleven thousand, three hundred thirty-one".