Base | Representation |
---|---|
bin | 11000101011110100… |
… | …00011110011001111 |
3 | 1021012120210212121221 |
4 | 30111322003303033 |
5 | 204120111141333 |
6 | 10031005504211 |
7 | 646256624026 |
oct | 142572036317 |
9 | 37176725557 |
10 | 13252443343 |
11 | 5690727917 |
12 | 269a272067 |
13 | 133278b569 |
14 | 8da0bd8bd |
15 | 5286b9d2d |
hex | 315e83ccf |
13252443343 has 2 divisors, whose sum is σ = 13252443344. Its totient is φ = 13252443342.
The previous prime is 13252443311. The next prime is 13252443359. The reversal of 13252443343 is 34334425231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13252443343 - 25 = 13252443311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13252443299 and 13252443308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13252443383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626221671 + 6626221672.
It is an arithmetic number, because the mean of its divisors is an integer number (6626221672).
Almost surely, 213252443343 is an apocalyptic number.
13252443343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13252443343 is an equidigital number, since it uses as much as digits as its factorization.
13252443343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 34.
Adding to 13252443343 its reverse (34334425231), we get a palindrome (47586868574).
The spelling of 13252443343 in words is "thirteen billion, two hundred fifty-two million, four hundred forty-three thousand, three hundred forty-three".
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