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132524746017047 is a prime number
BaseRepresentation
bin11110001000011111010010…
…011010010000100100010111
3122101020020112102001202200022
4132020133102122100210113
5114332241134440021142
61145505010003135355
736625411514566406
oct3610372232204427
9571206472052608
10132524746017047
113925447a23936a
1212a4422537455b
1358c4050995257
1424a23365c363d
15104c41590c6d2
hex7887d2690917

132524746017047 has 2 divisors, whose sum is σ = 132524746017048. Its totient is φ = 132524746017046.

The previous prime is 132524746016941. The next prime is 132524746017113. The reversal of 132524746017047 is 740710647425231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132524746017047 - 216 = 132524745951511 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132524746017047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132524776017047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66262373008523 + 66262373008524.

It is an arithmetic number, because the mean of its divisors is an integer number (66262373008524).

Almost surely, 2132524746017047 is an apocalyptic number.

132524746017047 is a deficient number, since it is larger than the sum of its proper divisors (1).

132524746017047 is an equidigital number, since it uses as much as digits as its factorization.

132524746017047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7902720, while the sum is 53.

The spelling of 132524746017047 in words is "one hundred thirty-two trillion, five hundred twenty-four billion, seven hundred forty-six million, seventeen thousand, forty-seven".