Base | Representation |
---|---|
bin | 11000101011111010… |
… | …11100100001010111 |
3 | 1021012122110222022021 |
4 | 30111331130201113 |
5 | 204120323043111 |
6 | 10031040514011 |
7 | 646300312033 |
oct | 142575344127 |
9 | 37178428267 |
10 | 13253331031 |
11 | 5691183846 |
12 | 269a61b907 |
13 | 1332a0c615 |
14 | 8da2711c3 |
15 | 5287e2d71 |
hex | 315f5c857 |
13253331031 has 2 divisors, whose sum is σ = 13253331032. Its totient is φ = 13253331030.
The previous prime is 13253330887. The next prime is 13253331059. The reversal of 13253331031 is 13013335231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13253331031 - 223 = 13244942423 is a prime.
It is a super-2 number, since 2×132533310312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13253330987 and 13253331005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13253371031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626665515 + 6626665516.
It is an arithmetic number, because the mean of its divisors is an integer number (6626665516).
Almost surely, 213253331031 is an apocalyptic number.
13253331031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13253331031 is an equidigital number, since it uses as much as digits as its factorization.
13253331031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2430, while the sum is 25.
Adding to 13253331031 its reverse (13013335231), we get a palindrome (26266666262).
The spelling of 13253331031 in words is "thirteen billion, two hundred fifty-three million, three hundred thirty-one thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •