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132539105117 is a prime number
BaseRepresentation
bin111101101101111110…
…0100011111101011101
3110200002212201011001002
41323123330203331131
54132420002330432
6140515421000045
712401304543116
oct1733374437535
9420085634032
10132539105117
1151233962411
122182b0b3025
13c662c463b3
1465b47b920d
1536aac15e62
hex1edbf23f5d

132539105117 has 2 divisors, whose sum is σ = 132539105118. Its totient is φ = 132539105116.

The previous prime is 132539105033. The next prime is 132539105143. The reversal of 132539105117 is 711501935231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128057338201 + 4481766916 = 357851^2 + 66946^2 .

It is an emirp because it is prime and its reverse (711501935231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132539105117 is a prime.

It is a super-2 number, since 2×1325391051172 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132539105197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66269552558 + 66269552559.

It is an arithmetic number, because the mean of its divisors is an integer number (66269552559).

Almost surely, 2132539105117 is an apocalyptic number.

It is an amenable number.

132539105117 is a deficient number, since it is larger than the sum of its proper divisors (1).

132539105117 is an equidigital number, since it uses as much as digits as its factorization.

132539105117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28350, while the sum is 38.

The spelling of 132539105117 in words is "one hundred thirty-two billion, five hundred thirty-nine million, one hundred five thousand, one hundred seventeen".